# Indefinite Integration of *e*^{x}

How to solve the indefinite integration of *e*^{x} problems: formula, example, and its solution.

## Formula

∫ *e*^{x} *dx* = *e*^{x} + *C*

This is true because

[*e*^{x} + *C*]' = *e*^{x}.

Derivative of *e*^{x}

## Example

(*e*^{x})^{2} - 1^{2} = (*e*^{x} + 1)(*e*^{x} - 1)

Factoring the difference of squares

Cancel (*e*^{x} - 1)

on both of the numerator and the denominator.

∫ *e*^{x} *dx* = *e*^{x}

So (given) = *e*^{x} + *x* + *C*.