Indefinite Integration of ax
How to solve the indefinite integration of ax problems: formula, example, and its solution.
∫ ax dx = (1/ln a)⋅ax + C
This is true because
[(1/ln a)⋅ax + C]' = (ln a / ln a)⋅ax
Derivative of ax
∫ 6x dx = (1/ln 6)⋅6x
∫ 2x dx = (1/ln 2)⋅2x
So (given) = (1/ln 6)⋅6x + (1/ln 2)⋅2x + C.