Indefinite Integration of 1/x
How to solve the indefinite integration of 1/x problems: formula, example, and its solution.
∫ 1/x dx = ln |x| + C
This is true because
[ln |x| + C]' = 1/x.
Derivative of ln |x|
Split the fraction into three parts.
∫ 1/x dx = ln |x|
So (given) = (1/2)x2 - x + 2 ln |x| + C.
Indefinite integration of polynomials